SAT MathAlgebra5 Practice Questions

Systems of Inequalities — SAT Math Explained

Two or more linear inequalities considered simultaneously. The solution is the overlapping region (intersection) of all individual shaded regions — every point that satisfies ALL inequalities at once.

The Core Idea

Each inequality restricts the coordinate plane. When you have multiple restrictions simultaneously, only the region satisfying all of them qualifies. This overlap is the feasibility region.

Step-by-Step: How to Approach Systems of Inequalities

1

Graph the first inequality: draw the boundary line (solid/dashed), shade the solution region

2

On the SAME coordinate plane, graph the second inequality the same way

3

Identify the region where the shading overlaps — this is the solution set

4

To confirm, pick a point from the overlapping region and verify it satisfies ALL inequalities

No Solution Case

If the shaded regions don't overlap at all, the system has no solution — no point satisfies all conditions simultaneously

Real World Application

Linear programming: maximizing profit or minimizing cost subject to constraints (budget, capacity, time)

Scheduling: finding times that satisfy all participants' availability

Nutrition planning: finding meal combinations that meet all dietary requirements

Common Errors to Avoid

Only shading for one inequality and forgetting the other

Identifying the union (all shaded area) instead of the intersection (overlap only)

Not checking a point from the final region in all original inequalities

Practice: Systems of Inequalities

5 SAT-style questions. Select your answer and get an instant explanation.

5 Q's
Question 1 of 5Easy

Which point satisfies BOTH inequalities: y > x and y < 5?

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